Theoretical Strength and Test Strength of Consolidation of Container Cargo

In order to better reinforce the goods in the container , packers around the world usually calculate how many binding straps they need to use inside the container in the case of securely bound goods. How much force can be taken by the binding point naturally will Was taken into account. Sometimes the goods can be very heavy. Theoretically, the limited binding points in the container are not enough to play a role in the reinforcement of the safe goods , because there are many details and other external forces that need to be taken into consideration. I would like to think that the nominal strength of the container binding point proposed by the official certification system ISO 1496-1 : 1990 will not be ideal?

Below I will tell you a real-life example and tell a very different story. We have a client who has a venue that can simulate rail transportation. We use the actual railway transition as an example of testing. We have placed a gravimetric instrument in the railcar that can measure the effect of gravity acceleration in each direction. The rated strength that a bundling point at the bottom of a container can withstand is 1000kg , and the rated strength of the top binding point is 500kg . In the image below you can see that some of the wood is stacked in a regular shape and placed in a container, weighing up to 16 tons. The timber is reinforced with solid straps and straps from Gusset and is secured to the 8 bundling points evenly distributed in the container. You can watch Tudou's test video on Tudou.com. Our company created this video to show you that often the bundled points in the container can support more cargo weight than estimated.

In the end, what exactly is the result of the test?

The capacity of containers in the process of train transition is as high as 12G! ! ! No bundled points are damaged, and our cordstrap Cordless straps and straps are also harmless.

Let's calculate how big each binding point is:

1) cargo force = 12G*16,000 kg=192,000kg

2) Less friction 16,000*0.5 Static friction factor *0.7=192,000-5.600=186.400kg

3) Deduct the force of wood itself +/- 1.400kg=186.400-1.400kg=185.000kg

4) The effect of all the binding points is 185.000kg

5) After the 8 container bundling points evenly distribute 185.000kg of force, the force at each bundling point is 23.1 tons.

This is an algorithm that the ISO certification authority obtained for each tonnage capacity that can withstand 23 tons.